For the network shown in the given figure, voltage VB will

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For the network shown in the given figure, voltage V_B will be

1. (j 5.33) V
2. (5.33) V
3. (– j 5.33) V
4. (j 3.33) V

Correct Option: A

Drawing equivalent circuit, we have

Current , I =	8j - 2j	=		-	2		amp
	9j				3

Then, V_B = 8j + 4j.I

= 8j -	8j
	3

=	16j	= 5.33j V
	3