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For the circuit shown in the given figure, if input impedance Z1 at port 1 is given by
Z1 = K1 (s + 2) s + 5
then input impedance Z2 at port 2 will be
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K2(s + 3) s + 5
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K2(s + 2) s + 3
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K2 s s + 5
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K2 s s + 2
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Correct Option: C
| Z1 = K1 | ||
| s + 5 |
| ∴ Z1 = R1 | ||
| R1 + R2 + Ls |
| = | R1L | ![]() | ![]() | ![]() | ![]() | |
| L + (s) | ||||||
| L | ![]() | ![]() | ![]() | ![]() | ||
| L + (s) | ||||||
| = | R1 | ![]() | ![]() | ![]() | ![]() | |
| L + (s) | ||||||
![]() | ![]() | ![]() | ![]() | |||
| L + (s) | ||||||
∴ R1 = K1
| = 2 , | = 5 | |||
| L | L |
| Again , R2 = | K1 , L = | |||
| 3 | 3 |
| ∴ Z2 = | ||
| Ls + R2Cs |
| = | ![]() | ![]() | ![]() | ![]() | ![]() | ![]() | |||
| 3s | 3K1 | ||||||||
![]() | ![]() | sK1 + | ![]() | ![]() | ![]() | ![]() | |||
| 3 | 3K1 | ||||||||
| = | s | ![]() | ![]() | |
| 3K1 | = | |||
| (s + 5) | (s + 5) | |||
| ∴ K2 = | K1 | |
| 3 |



