-
The two electric sub-networks N1 and N2 are connected through three resistors as shown in the figure below. The voltage across 5 Ω resistor and 1 Ω resistor are given to be 10V and 5V respectively. Then voltage across 15 Ω resistor is
-
- – 105 V
- + 105 V
- – 15 V
- + 15 V
- – 105 V
Correct Option: A
By KCL, if we take a cutset along all three branches, then total current at the junction is zero.
i.e. I 1 + I 2 + I 3 = 0
| ⇒ | + I2 + | = 0 | ||
| 5 | 1 |
⇒ I2 = 7A
and V = – 105 V.
