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In respect of the 2-port network shown in the given figure, admittance parameters are :
Y11 = 8 mho, Y12 = Y21 = – 6 mho and Y22 = 6 mho. The values of YA, YB and YC (in units of mho) will be respectively
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- 2, 6 and – 6
- 2, 6 and 0
- 2, 0 and 6
- 2, 6 and 8
Correct Option: C
From the circuit, I1 = (V1 – V2) YC + V1 .YA
= – V1 (YA + YC) – V2. YC ....(i)
I2 = V1YC + V2 (YB + YC) ...(ii)
YA + YC = Y11 = 8 Ω
YC = Y12 = – Y21 = 6 Ω
YB + YC = Y22 = 6 Ω
∴ YA = 2, YB = 0, YC = 6 Ω