In the circuit shown, i(t) is a unit step current. The steady-state

In the circuit shown, i(t) is a unit step current. The steady-state value of v(t) is

At steady-state condition, capacitor is open and inductor is shorted, then

current through 6 Ω = 1 ×	3	=	1	Ω
	3 + 6		3

and V(t) = L	di	+ 6i
	dt

= 0 +		6 ×	1		= 2 volts
			3