For the circuit show in the (given figure) i(t) under steady

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For the circuit show in the (given figure) i(t) under steady state is

1. zero
2. 5
3. 7.07 sin t
4. 7.07 sin (t – 45°)

Correct Option: D

d.c. voltage 5V would encounter an open circuit in the capacitor and hence the current is 0.

For a.c , i(t) =	10 sin t
	1 + j2 +	1
		j

=	10 sin t	=	10	sin (t - 45°)
	1 + j		√2

= 7.07 sin (t – 45°)