In an unbalanced three phase system, phase current Ia =

In an unbalanced three phase system, phase current I_a = 1 ∠(– 90°) pu, negative sequence current I_b2 = 4∠(– 150°)pu, zero sequence current I_C0 = 3∠90° pu. The magnitude of phase current I_b in pu is

I _a = 1∠ – 90p.u
I _b2 = 4 ∠ – 150 p.u
I _c0 = 3 ∠ 90 p.u
I_a = I_a₁ + I_a₂ + I_a₀
Now I_b₂ = α I_a₂