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In the circuit shown below, if the source voltage Vs =100 ∠ 53.13° V then the Thevenin’s equivalent voltage in Volts as seen by the load resistance RL is
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- 100 ∠90°
- 800 ∠0°
- 800 ∠90°
- 100 ∠60°
Correct Option: C
Given : Vs = 100 ∠53.13° V
To find : Thevenin’s voltage across Load resistonce
Solution
* For V'th open it.
* Opening, then I2 = 0
* When I2 = 0, then j40I2 = 0 {voltage source will short circuit)
∴ Circuit became
* VTH = 10VL1 because no-current flowing through circuit.
VTH = | = | |||
3 + 4j | 3 + 4j |
From rectangular domain to polar domain.
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