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The impedance looking into nodes 1 and 2 in the given circuit is
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- 50 Ω
- 100 Ω
- 5 kΩ
- 10.1 kΩ
Correct Option: A
After connecting a voltage source of V
Rth = | = | = 50 Ω | ||
I | I |
V1 = V2
⇒ (10k) (– ib) = 100 (I + 99ib + ib)
and – 10000ib = 100I + 100 × 100ib
= 100I + 10000ib
⇒ – 20000ib = 100I
ib = - | ![]() | ![]() | I = | ![]() | - | ![]() | ||
20000 | 200 |
= 50I
⇒ V/I = 50 Ω