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The switch in the circuit has been closed for a long time. It is opened at t = 0. At t = 0+, the current through the 1 μF capacitor is
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- 0 A
- 1 A
- 1.25 A
- 5 A
Correct Option: B
Circuit at t = 0– (at steady state)
| Initial voltage, Vc (0–) = | × 5 = 4 V | |
| 1 + 4 |
Circuit at t = 0+
| ic(0+) = IB = | = 1 amp | |
| 4 |
| i = | e-t / RC | |
| R |
