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The equivalent capacitance of the input loop of the circuit shown below is
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- 2μ F
- 100μF
- 200μF
- 4μF
Correct Option: A
We know, Q = CV
But voltage across capacitor is constant.
C ∝ Q
⇒ C ∝ i
∴ Ctotal ∝ (i1 + i2)
Cin ∝ li
| ∴ Cin = | ||
| (i1 + i2) |
| Ctotal = | (100 μF) | |
| (i1 + 49i1) |
| = | (100 μF) = 2μF | |
| 50i1 |
Alternately
| Vin = 2RI1 + | 50 | |
| jωC |
| I1 = 2RI1 + | I1 | |
| jωCeq |
| ∴ Ceq = | = 2 μF | |
| 50 |
