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A capacitor consists of two metal plates each 500 × 500 mm2 and spaced 6 mm apart. The space between the metal plates is filled with a glass plate of 4 mm thickness and a layer of paper of 2 mm thickness. The relative permittivities of the glass and paper are 8 and 2 respectively. Neglecting the fringing effect, the capacitance will be (Given that ε 0 = 8.85 × 10– 12 F/m)
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- 983.33 pF
- 1475 pF
- 6637.5 pF
- 9956.25 pF
Correct Option: B
A1 = A2 = 500 × 500 mm2 = 25 × 10 – 2
εr1 = 8, εr2 = 2; d1 = 4, d2 = 2
∴ Ceq = | = | . | |||
d1 | d2 | ||||
C1 + C2 | + | ||||
d 1 | d 2 |
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∴ Ceq = | ||
εr1d2 + εr2d1 |
= | = 1475 μF | |
8 × 2 + 2 × 4 |