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Divergence of the vector field V (x, y, z) = – (x cos xy + y) i + (y cos xy) j + (sin z2 + x2 + y2) k is
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- 2z cos z2
- sin xy + 2z cos z2
- x sin xy – cos z
- none of these
Correct Option: A
V (x, y, z) = – (x cos xy + y) i + (y cos xy) j + (sin z2 + x 2 + y 2) k
| Divergence = ∇ .V = | + | + | |||
| ∂x | ∂y | ∂z |
= – cos xy + x (sin xy) (y) + cos xy – y (sin xy) x + 2z cos z2 = 2z cos z2
