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The circuit shown in figure has two sources connected in series. The instantaneous voltage of AC source (in volt) is given by v(t) = 12sin t. If the circuit is in steady-state, then the rms value of current (in Ampere) flowing in circuit is _______.
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- 0
- 1
- 5
- 10
Correct Option: D
Applying superposition theorem, Consider D.C. source
| I = | = | = 8 Amp | ||
| R | 1 |
Consider A.C. source
XL = ωL = 1 × 1 = 1 Ω
| Vrms = | = | = 6 √2 Volt | ||
| √2 | √2 |
= √2 Ω
| Irms = | = | = 6 Amp | ||
| Z | √2 |
We know that, (Irms)2 = (Idc)2 + (Iac)2
= (8)2 + (6)2 = 64 + 36 = 100
I rms = 10 Amp
