Consider the two systems S1 : y[n] = x[n + 1], n

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Consider the two systems

S₁ : y[n] = x[n + 1],        n ≥ 0
x[n],        n ≤ - 1

S₂ : y[n] = x[n /2],        n even
0        n odd

The invertible system is

1. S₁
2. S₂
3. Both S₁ and S₂
4. None of these

Correct Option: B

S₂ is invertible system
y[n] = x[2n],
S₂ is not invertible because δ[n], 2δ[n] etc. result in
y[n]= 0.