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Fourier Series coefficient of time-domain signal is
X[k] = jδ[k – 1]– jδ[k + 1] + δ[k + 3] + δ[k – 3], ωo = 2π
then corresponding time domain signal will be
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- 2(cos 3πt – sin πt)
- – 2(cos 3πt – sinπt)
- 2(cos 6πt – sin 2πt)
- – 2(cos 6πt – sin 2πt)
Correct Option: C
= jej2πt – je– j2πt + ej6πt + e– j6πt
= – 2sin 2πt + 2cos 6πt