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The signum function is given by
sgn(x) = x/|x|, x≠0 0 x = 0
The fourier series expansion of sgn(cos(t)) has
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- only sine terms with all harmonics
- only cosine terms with all harmonics
- only sine terms with even numbered harmonics
- only cosine terms with odd numbered harmonics
Correct Option: D
The signum function is given by,
sgn(x) = | ![]() | |||
0; | x = 0 |
Similarly,
sgn(cos t) = | ![]() | |||
- 1; | cos t = 0 |
cos t / |cos t| = | ![]() | |||
- 1; | cos t < 0 |

It is even function and show half wave symmetry. It contains only cosine term with odd numbered harmonics. a0 = 0
bn = 0
an = | ![]() | |||
≠0; | n = odd |
Sgn(Cost) = a1 cosωt + a3 cos3ωt + a5cos5ωt +...