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The response h(t) of a linear time invariant system to an impulse δ(t), under initially relaxed condition is h(t) = e–t + e–2t. The response of this system for a unit step input u(t) is
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- u(t) + e–t + e–2t
- (e–t + e–2t) u(t)
- (1.5 – e–t – 0.5e–2t) u(t)
- e–t δ(t) + e–2t u(t)
Correct Option: C
Impulse response, H(s) = α h(t)
= | + | ||
(s + 1) | (s+ 2) |
Step response = L-1 | ![]() | + | ![]() | ||
(s + 1) | (s+ 2) |
= L-1 | ![]() | ![]() | - | ![]() | + | ![]() | - | ![]() | ![]() | ||||
s | s + 2 | s | (s + 2) |
= (1 – e–t + 0.5 – 0.5e–2t)u(t)
= (1.5 – e–t – 0.5e–2t)u(t)