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x [n] = 0; n < – 1, n > 0, x [– 1] = – 1, x[0] = 2 is the input and y [n] = 0; n < – 1, n > 2, y[– 1] = – 1 = y[1], y [0] = 3, y [2] = – 2 is the output of a discret e-time LTI system. The system impulse response h[n] will be
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- h[n] = 0; n < 0, n > 2, h[0] = 1, h[1] = h[2] = – 1
- h[n] = 0; n < – 1, n > 1, h[– 1] = 1, h[0] = h[1] = 2
- h[n] = 0; n < 0, n > 3, h[0] = – 1, h[1] = 2, h[2] = 1
- h[n] = 0; n < – 2, n > 1, h[– 2] = h[1] = h[– 1] = – h[0] = 3
Correct Option: A
NA