Direction: 16 players participated in world Chess Championship. These 16 players are seeded from seed 1 to seed 16 with seed 1 as the best rank. These 16 players are divided in two groups such that all the odd numbered seed are in group A and all the even numbered seed are in group B.
In each group each team plays with each other exactly once and no match ended in a tie. For a win winner awarded 2 points while looser 0 points. From each group top two players based on the points scored are advanced to the next stage i.e semifinal stage. In semifinal stage top scorer of one group plays with 2nd best scorer of the other group. Winners of the semi-final play for the final while loosers play for the 3rd place.
An Upset is when a lower seeded player beat a higher seeded player.
In case of same number of points at the end of the 1st stage there is a complex tie breaker rule which is used to determine the rank.
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If upset caused by a winner is 3 then which lowest seed can win the tournament?
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- 14
- 13
- 8
- None of these
Correct Option: B
Total number of matches in the 1st stage is 4 x 7 = 28, lets consider group 1 here if seed 1 won all the matches then remaining 21 matches or points can be equally distributed to 7 player (3 points each) and the lowest possible player would advance to next stage with tie breaker rule. In this stage seed 13 can get 3 points after 2 upsets caused by him. So from this group seed 1 and 13 would advance to the next stage. Similarly from 2nd group seed 2 and 14 would advance to the next stage.
Now as per the rule seed 1 will play with seed 14 and seed 2 will play with seed 13,
If seed 13 and 4 meet in the tournament then seed 13 will win with 3 upset.
