When a unit impulse voltage is applied to an inductor of

When a unit impulse voltage is applied to an inductor of 1 H, the energy supplied by the source is

Current that flows is given by V (s) = sL I (s)
⇒ 1 = s.1. I(s)

⇒ I(s) =	1
	s

∴ i(t) = u(t) = 1 Amp.

Energy supplied =	1	LI² =	1	× 1 × 1
	2		2

=	1	J
	2