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A two terminal black box contains one of the R.L.C. elements. The black box is connected to a 220 volts A.C. supply. The current through the source is I. When a capacitance of 0.1F is inserted in the series between the source and the box, the current through the source is 2I. The element is
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- a resistance
- an inductance
- a capacitance of 0.5F
- it is not possible to determine the element.
Correct Option: B
| Initially , I = | ||
| R + jX |
When capacitance inserted,
| 2I = | ||
| R + jX - jωC |
| ⇒ | + | |||
| R + jX | R + jX - (j / ωC) |
| ⇒ 2R + 2jX - | = R + jX | |
| ωC |
| ⇒ R + jX = | ||
| ωC |
| X = | ||
| ωC |
Here ‘+’ ve sign element is inductance