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A linear time invariatiant system has an impulse response e2t, t > 0. If the initial conditions are zero and the input is e3t, the output for t > 0 is
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- e3t – e2t
- e5t
- e3t + e2t
- None of these
Correct Option: A
Output C(s) = H (s). R (s) = | . | = | then C (t) = L – 1 [C(s)] | |||
s - 2 | s - 3 | (s - 2)(s - 3) |
= L-1 | ![]() | ![]() | - L-1 | ![]() | ![]() | = e3t - e2t | ||
(s - 3) | (s - 2) |