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The bilateral Laplace transform of x(t) = et/2 u(t) + e–t u(t) + et u(–t) will be
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6s² + 2s - 2 , Re (s) < - 0.5 (2s + 1)(s² - 1) -
6s² + 2s - 2 ,- 1 > Re (s) > - 0.5 (2s + 1)(s² - 1) -
1 + 1 + 1 ,- 1 < Re (s) < - 0.5 s + 0.5 s + 1 s - 1 -
1 + 1 + 1 , 0.5 < Re (s) < - 0.5 s + 0.5 s + 1 s - 1
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Correct Option: D
| = | + | - | |||
| s + 0.5 | s + 1 | s - 1 |
Re(s) > – 0.5, Re (s) > – 1, Re(s) < 1
⇒ – 0.5 < Re (s) < 1
