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The speed of an engine varies from 210 rad/s to 190 rad/s. During cycle the change in kinetic energy is found to be 400 Nm. The inertia of the flywheel in kg-m² is
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- 0.10
- 0.20
- 0.30
- 0.40
Correct Option: A
We know, ΔE = Iω²CS
Here, ω = 200; ΔE = 400
| Cs = | ||
| ωmax + ωmin |
| = | = 0.1 | |
| 200 |
ΔE = 400 N – m
| ∴ I = | = | = .10 | ||
| ω²CS | (200)² × 01 |
