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The torque (in Nm) exerted on the crank shaft of a two stroke engine can be described as T = 10000 + 1000 sin 2θ - 1200 cos 2θ, where θ is the crank angle as measured from inner dead center position. Assuming the resisting torque to be constant, the power (in kW) developed by the engine at 100 rpm is _________.
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- 104.719 kW
- 104.59 kW
- 105.65 kW
- 105 kW
Correct Option: A
T = 10000 + 1000 sin2θ – 1200 cos2θ
N = 100 rpm
| ω = | = 10.472 rad/s | |
| 60 |
| Tmean = | 2π∫0[10000 + 1000sin2θ - 1200 cos2θ]dθ | |
| 2π |
By solving, we get Tmean = 10000 N-m
| Power = 10000 × | ||
| 60 |
= 104719.75 W
= 104.719 kW
