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For a certain engine having an average speed of 1200 rpm, a flywheel approximated as a solid disc, is required for keeping the fluctuation of speed within 2% about the average speed. The fluctuation of kinetic energy per cycle is found to be 2 kJ. What is the least possible mass of the flywheel if its diameter is not to exceed 1 m?
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- 40 kg
- 51 kg
- 62 kg
- 73 kg
Correct Option: B
Average speed, N = 1200 rpm
Co-efficient of fluctuation of speed
= Cs = | = 2% = 0.02 | |
ω |
Fluctuation of kinetic energy = ΔE = 2 × 10³J
Now, ΔE = | Iω²1 - | Iω²2 = | I(ω²1 - ω²2) | |||
2 | 2 | 2 |
Since | = ω | |
2 |
= I | ![]() | ![]() | (ω1 - ω2) | |
ω |
Iω | .ω | |
ω |
= Iω²cs.
⇒ 2 × 10² = | MR².ω².C²s | |
2 |
where R = Radius of disc
= | M × | ![]() | ![]() | ² | × | ![]() | ![]() | × 0.02 | |||
2 | 2 | 60 |
∴ M = | ||
0.02 × (2 × π × 1200)² |
= 50.65 ≈ 51 kg.