Direction: The following data relate to an orthogonal turning process: back rake angle = 15 deg. width of cut = 2 mm chip thickness = 0.4 mm, feed rate = 0.2 mm/rev
-
The shear angle is
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- 14°
- 25°
- 29°
- 75°
Correct Option: C
α = 15°
W = 2 mm
t2 = 0.4mm
fr = 0.2 mm/rev = t1
| r = | = | = | |||
| t2 | 0.4 | 2 |
r = 0.5
| φ = tan-1 |  |  | |
| 1 - r sin∝ |
| φ = tan-1 | | | |
| 1 - 0 sin 15 |
φ = 0
