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Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

Direction: The following data relate to an orthogonal turning process: back rake angle = 15 deg. width of cut = 2 mm chip thickness = 0.4 mm, feed rate = 0.2 mm/rev

  1. If the cutting force and the thrust force are 900 N and 810 N, the mean strength in MPa
    1. 137.94
    2. 477.91
    3. 500.58
    4. 635.84
Correct Option: B

Fc = 900 N,
Ft = 810 N

tanβ =  
FT
+ tanα
Fc
1 -
FT
tanα
Fc

tanβ =  
810
+ tan 15°
900
1 -
810
tan 15°
900

β = 56.98°
Fs
=
Rcos(φ + β - ∝)
FcRcos(β - ∝)

Fs = 394.56 N
Cs =
Fs
× sinφ =
394.56
× sin 29
Wt12 × 0.2

Cs = 478 mpa



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