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Two different tools A and B having nose radius of 0.6 mm and 0.33 mm respectively are used to machine C-45 steel employing feed rate of 0.2 mm/rev and 0.1 mm/rev respectively. The tool that gives better finish and the value of ideal surface roughness are
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- Tool A and 4.166 μrespectively
- Tool B and 3.78 μm respectively
- Tool A and 8.333 μm respectively
- Tool B and 8.333 μm respectively
Correct Option: B
RA = 0.6 mm. RB = 0.33 mm
FA = 0.2 mm/rev FB = 0.1 mm/rev
| (Hmax)A = | = | = 0.000833 mm | ||
| 8RA | 8 × 0.6 |
= 8.33um
| (Hmax)B = | = | = 3.78 mm | ||
| 8RB | 8 × 0.33 |
Tool B have higher surface finish them A.
