-
The fundamental period for the given signal
x(n) = Re 
e jnπ 
+ Img 
e jnπ 
12 18
-
- 72
- 36
- 24
- None of these
Correct Option: A
| Given signal, x(n) = Re | ![]() | e | ![]() | + Img | ![]() | e | ![]() | ||
| 12 | 18 |
| x(n) = cos | + j sin | |||
| 12 | 18 |
Fundamental period of
| x1(n)= N1 = | m = | · m = 24 | ||
| Ω | ||||
| 12 |
Fundamental period of
| x2(n)= N2 = | m = | · m = 36 | ||
| Ω | ||||
| 18 |
Fundamental period of the signal x[n]. Greatest common mean (GCM) of x1[n] and x2[n]
GCM of 24 and 36 = 72.