-
The fundamental period for the given signal
x(n) = Re e jnπ + Img e jnπ 12 18
-
- 72
- 36
- 24
- None of these
Correct Option: A
Given signal, x(n) = Re | ![]() | e | ![]() | + Img | ![]() | e | ![]() | ||
12 | 18 |
x(n) = cos | + j sin | |||
12 | 18 |
Fundamental period of
x1(n)= N1 = | m = | · m = 24 | ||
Ω | ||||
12 |
Fundamental period of
x2(n)= N2 = | m = | · m = 36 | ||
Ω | ||||
18 |
Fundamental period of the signal x[n]. Greatest common mean (GCM) of x1[n] and x2[n]
GCM of 24 and 36 = 72.