-
The period for the signal
x(n) = e jnπ cos 
nπ 
is— 16 17
-
- 32
- 34
- 544
- 272
Correct Option: C
| Given x(n) = e | cos | ![]() | ![]() | |||
| 16 | 17 |
Fundamental period of
| x1(n) = e | ||
| 16 |
| or x1(n) = cos | + j sin | |||
| 16 | 16 |
| N1 = | = | · m = 32 | ||
| Ω | ||||
| 16 |
Fundamental period of
| x2(n) = cos | ![]() | ![]() | |||
| 17 |
| i.e., N2 = | = | · m = 34 | ||
| Ω | ||||
| 17 |
Fundamental period of the signal
x(n) = GCM of N1 and N2
= GCM of 32 and 34
| = | = 544 | |
| 2 |
Hence, alternative (C) is the correct choice.