-
The period for the signal
x(n) = e jnπ cos nπ is— 16 17
-
- 32
- 34
- 544
- 272
Correct Option: C
Given x(n) = e | cos | ![]() | ![]() | |||
16 | 17 |
Fundamental period of
x1(n) = e | ||
16 |
or x1(n) = cos | + j sin | |||
16 | 16 |
N1 = | = | · m = 32 | ||
Ω | ||||
16 |
Fundamental period of
x2(n) = cos | ![]() | ![]() | |||
17 |
i.e., N2 = | = | · m = 34 | ||
Ω | ||||
17 |
Fundamental period of the signal
x(n) = GCM of N1 and N2
= GCM of 32 and 34
= | = 544 | |
2 |
Hence, alternative (C) is the correct choice.