X is four years older than Y who is twice as old as Z. If

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X is four years older than Y who is twice as old as Z. If the total ages of X, Y and Z be 34, how old is X?

1. 8
2. 10
3. 12
4. 16

Correct Option: D

Suppose, the age of Z = P years
Age of Y = 2P years
Age of X = 2P + 4 years
According to question , the total ages of X, Y and Z = 34
P + 2P + (2P + 4) = 34
⇒ 5P = 34 – 4

∴ P =	30	= 6
	5

Age of X = 2P + 4 = 2 × 6 + 4 = 16 years