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Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the velocity of B when angle α = 60° ?
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- 5.8 m/s
- 9.8 m/s
- 10 m/s
- 17.3 m/s
Correct Option: D
Let after 1 sec angle become 60°. When the end A moves by 10 m left, the end B moves upward by BB′ = 10 × √3 = 10 × 1.73 = 17.3 m / s