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A body of 3 kg moves in the XY plane under the action of a force given by 6t î + 4t ĵ . Assuming that the body is at rest at time t = 0, the velocity of the body at t = 3s is
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- 6î - 6ĵ
- 18î + 6ĵ
- 18î + 12ĵ
- 12î + 18ĵ
Correct Option: C
F→ = 6t î + 4t ĵ
Fx = 6t , Fy = 4t
ax = | = 2t , ay = | |||
3 | 3 |
vx = 0 + 2t . t = 18 , for t = 3s
vy = 0 + | t.t = 12 for t = 3s | |
3 |
Velocity → 18î + 12ĵ