The Binding energy per nucleon of 3Li7 and 2He4 nuclei

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The Binding energy per nucleon of ₃Li⁷ and ₂He⁴ nuclei are 5.60 MeV and 7.06 MeV, respectively.
In the nuclear reaction ₃Li⁷ + ₁H¹ → ₂He⁴ + Q, the value of energy Q released is :

1. 19.6 MeV
2. – 2.4 MeV
3. 8.4 MeV
4. 17.3 MeV

Correct Option: D

BE of ₂He⁴ = 4 × 7.06 = 28.24 MeV

BE of	7	Li = 7 × 5.60 = 39.20 MeV
	3

Therefore, Q = 56.48 – 39.20 = 17.28 MeV.