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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is
(Given : 1 a.m.u = 931 MeV)
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- 26.7 MeV
- 6.675 MeV
- 13.35 MeV
- 2.67 MeV
Correct Option: B
Mass defect Δm = 0.02866 a.m.u.
Energy = 0.02866 × 931 = 26.7 MeV
As 1H2 + 1H2 → 2He4
Energy liberated per a.m.u = 13.35/2 MeV = 6.675 MeV
