Thermodynamics
- During an adiabatic process, the pressure of a gas is found to be proportional to the cube of
its temperature. The ratio of Cp for the gas is Cv
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According to question P ∝ T3
But as we know for an adiabatic process thepressure P ∝ γ Tγ - 1 So , γ = 3 ⇒ γ = 3 or, Cp = 3 γ - 1 2 Cv 2
Correct Option: C
According to question P ∝ T3
But as we know for an adiabatic process thepressure P ∝ γ Tγ - 1 So , γ = 3 ⇒ γ = 3 or, Cp = 3 γ - 1 2 Cv 2
- A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cyclic process is :
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∵ Internal energy is the state function.
∴ In cyclie process; ∆U = 0
According to 1st law of thermodynamics∆Q = ∆U + W
So heat absorbed
∆Q = W = Area under the curve
= – (2V) (P) = – 2PV
So heat rejected = 2PVCorrect Option: A
∵ Internal energy is the state function.
∴ In cyclie process; ∆U = 0
According to 1st law of thermodynamics∆Q = ∆U + W
So heat absorbed
∆Q = W = Area under the curve
= – (2V) (P) = – 2PV
So heat rejected = 2PV
- Which of the following relations does not give the equation of an adiabatic process, where terms have their usual meaning?
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Adiabatic equations of state are
PVγ = constant
TVγ–1 = constant
P1–γTγ = constant.Correct Option: A
Adiabatic equations of state are
PVγ = constant
TVγ–1 = constant
P1–γTγ = constant.
- One mole of an ideal gas goes from an initial state A to final state B via two processes : It first undergoes isothermal expansion from volume V to 3V and then its volume is reduced from 3V to V at constant pressure. The correct P-V diagram representing the two processes is :
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1st process is isothermal expansion which is only correct shown in option (d)
2nd process is isobaric compression which is correctly shown in option (d)Correct Option: D
1st process is isothermal expansion which is only correct shown in option (d)
2nd process is isobaric compression which is correctly shown in option (d)
- A gas is taken through the cycle ABCA, as shown in figure. What is the net work done by the gas ?
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Wnet = Area of triangle ABC
= 1 AC × BC 2 = 1 × 5 × 10-3 × 4 × 105 = 1000 J 2 Correct Option: A
Wnet = Area of triangle ABC
= 1 AC × BC 2 = 1 × 5 × 10-3 × 4 × 105 = 1000 J 2