Kinetic Theory
- At constant volume, temperature is increased then
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As the temperature increases, the average velocity increases. So, the collisions are faster.
Correct Option: B
As the temperature increases, the average velocity increases. So, the collisions are faster.
- When volume of system is increased twice and temperature is decreased half of its initial temperature, then pressure becomes
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NA
Correct Option: D
NA
- Two vessels separately contain two ideal gases A and B at the same temperature. The pressure of A being twice that of B. Under such conditions, the density of A is found to be 1.5 times the density of B. The ratio of molecular weight of A and B is :
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From PV = nRT
PA = ρAMA and PB = ρBMB RT RT
From question,= PA = ρA MA = 2 MA = 3 PB ρB MB MB 2 So, MA - 3 MB 4 Correct Option: A
From PV = nRT
PA = ρAMA and PB = ρBMB RT RT
From question,= PA = ρA MA = 2 MA = 3 PB ρB MB MB 2 So, MA - 3 MB 4
- At 10° C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is:
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Let the mass of the gas be m.
At a fixed temperature and pressure, volume is fixed.Density of the gas, ρ = m V Now ρ = m = m P PV nRT ⇒ m = x(By question) nRT
⇒ xT = constant ⇒ x1T1 = x2TB⇒ x2 ⇒ x1T1 = 283 x T2 383 ∴ T1 = 283K T2 = 383K Correct Option: D
Let the mass of the gas be m.
At a fixed temperature and pressure, volume is fixed.Density of the gas, ρ = m V Now ρ = m = m P PV nRT ⇒ m = x(By question) nRT
⇒ xT = constant ⇒ x1T1 = x2TB⇒ x2 ⇒ x1T1 = 283 x T2 383 ∴ T1 = 283K T2 = 383K
- If Cs be the velocity of sound in air and C be the r.m.s velocity, then
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Velocity of sound (CS) = √γP/ρ
R.M.S. velocity of gas molecules = √3P/ρCS √ γP × ρ = √ γ C ρ 3P 3 ⇒ Cs = C × √ γ 3 Correct Option: C
Velocity of sound (CS) = √γP/ρ
R.M.S. velocity of gas molecules = √3P/ρCS √ γP × ρ = √ γ C ρ 3P 3 ⇒ Cs = C × √ γ 3