Strength Of Materials Miscellaneous


Strength Of Materials Miscellaneous

Strength Of Materials

  1. Two solid circular shafts of radii R1 and R2 are subjected to same torque. The maximum shear stresses developed in the two shafts are τ1 and τ2. If R1/R2 = 2, then τ21 is ______.









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    R1
    = 2
    R2

    T1 = T2.
    =
    τJ
    +
    τJ
    r1r2

    τ1d41
    =
    τ2d42
    d1d2

    τ1
    =
    2
    =
    1
    τ118

    d1d2
    τ2
    = 8
    τ1

    Correct Option: A

    R1
    = 2
    R2

    T1 = T2.
    =
    τJ
    +
    τJ
    r1r2

    τ1d41
    =
    τ2d42
    d1d2

    τ1
    =
    2
    =
    1
    τ118

    d1d2
    τ2
    = 8
    τ1


  1. Consider a stepped shaft subjected to a twisting moment applied at B as shown in the figure. Assume shear modulus, G = 77 GPa. The angle of twist at C (in degree) is _______.









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    Angle of twist at (C) = Angle of twist at (B)

    ⇒ θ =
    TL
    GJ

    10 × 0.5 × 32
    77 × 109 × π × .024

    ⇒ 0.236050

    Correct Option: A

    Angle of twist at (C) = Angle of twist at (B)

    ⇒ θ =
    TL
    GJ

    10 × 0.5 × 32
    77 × 109 × π × .024

    ⇒ 0.236050



  1. A hollow shaft (d0 = 2di where d0 and di are the outer and inner diameters respectively) needs to transmit 20 kW power at 3000 RPM. If the maximum permissible shear stress is 30 MPa, d0 is









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    P = Tω

    20 × 10³ = T ×
    2π × 3000
    60

    ∴ T = 63.662 N– m
    Now
    T
    =
    τ
    Ipr

    So,
    63.662
    =
    30 × 106
    (r0 = d),
    π/32(15d41)d1

    ∴ d1 = 11.295 mm
    ∴ d0 = 2d1 = 22.59 mm

    Correct Option: B

    P = Tω

    20 × 10³ = T ×
    2π × 3000
    60

    ∴ T = 63.662 N– m
    Now
    T
    =
    τ
    Ipr

    So,
    63.662
    =
    30 × 106
    (r0 = d),
    π/32(15d41)d1

    ∴ d1 = 11.295 mm
    ∴ d0 = 2d1 = 22.59 mm


  1. A frame is subjected to a load P as shown in the figure. The frame has a constant flexural rigidity EI. The effect of axial load is neglected. The deflection at point A due to the applied load P is









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    Strain energy (t) = L0
    xdx
    + L0
    ydx
    2EI2EI

    Mx = Px    MyPy
    1
    Pδ = L0
    (px)²dx
    + L0
    (px)²dx
    22EI2EI

    =
    2
    P²L²
    =
    1
    P ×
    4
    PL³
    3EI23EI

    δ =
    4
    PL³
    3EI

    Correct Option: D

    Strain energy (t) = L0
    xdx
    + L0
    ydx
    2EI2EI

    Mx = Px    MyPy
    1
    Pδ = L0
    (px)²dx
    + L0
    (px)²dx
    22EI2EI

    =
    2
    P²L²
    =
    1
    P ×
    4
    PL³
    3EI23EI

    δ =
    4
    PL³
    3EI



  1. A simply supported beam of length 2L is subjected to a moment M at the mid-point x = 0 as shown in the figure. The deflection in the domain 0 < x < L is given by
    w =
    - Mx
    (L - x)(x + c)
    12EIL

    where E is the Young's modulus, I is the area moment of inertia and C is a constant (to be determined).









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    ΔBA =
    (first moment area APB)
    EI


    =
    -1
    M
    ×
    1
    × L × 2
    L
    M
    EI2232EI

    =
    ML²
    6EI

    Slope at A =
    ΔBA
    =
    ML
    L6EI

    Correct Option: C

    ΔBA =
    (first moment area APB)
    EI


    =
    -1
    M
    ×
    1
    × L × 2
    L
    M
    EI2232EI

    =
    ML²
    6EI

    Slope at A =
    ΔBA
    =
    ML
    L6EI