Waves
- Equation of a progressive wave is given by
y = 4sin 
π 
t - x 
+ π 
5 9 6
Then which of the following is correct?
-
View Hint View Answer Discuss in Forum
The standard equation of a progressive wave is
y = a sin 2π t - x + φ T λ
The given equation can be written asy = 4 sin 2π t - x + φ 10 18 6
∴ a = 4 cm, T = 10 s, λ = 18 cm and φ = π/6
Hence, (b) is correct.Correct Option: B
The standard equation of a progressive wave is
y = a sin 2π t - x + φ T λ
The given equation can be written asy = 4 sin 2π t - x + φ 10 18 6
∴ a = 4 cm, T = 10 s, λ = 18 cm and φ = π/6
Hence, (b) is correct.
- The velocity of sound in any gas depends upon
-
View Hint View Answer Discuss in Forum
Velocity of sound in any gas depends upon density and elasticity of gas.
Correct Option: B
Velocity of sound in any gas depends upon density and elasticity of gas.
- The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?
-
View Hint View Answer Discuss in Forum
Difference in two successive frequencies of closed pipe 2v/4l = 260 – 220 = 40 Hz
or 2v/4l = 40 Hz
⇒ v/4l = 20Hz
Which is the fundamental frequency of system of closed organ pipe.Correct Option: A
Difference in two successive frequencies of closed pipe 2v/4l = 260 – 220 = 40 Hz
or 2v/4l = 40 Hz
⇒ v/4l = 20Hz
Which is the fundamental frequency of system of closed organ pipe.
- An air column, closed at one end and open at the other, resonates with a tuning fork when the smallest length of the column is 50 cm. The next larger length of the column resonating with the same tuning fork is :
-
View Hint View Answer Discuss in Forum
For a closed organ pipe first minimum resonating length
L1 = λ/4 = 50 cm
∴ Next or second resonating length, L2
= 3λ/4 = 150 cm.Correct Option: C
For a closed organ pipe first minimum resonating length
L1 = λ/4 = 50 cm
∴ Next or second resonating length, L2
= 3λ/4 = 150 cm.
- A uniform rope of length L and mass m1 hangs vertically from a rigid support. A block of mass m2 is attached to the free end of the rope. A transverse pulse of wavelength λ1 is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is λ2 the ratio λ2/λ1 is
-
View Hint View Answer Discuss in Forum
From figure, tension T1 = m2g
T2 = (m1 + m2)g
As we know
Velocity ∝ √T So,
λ ∝ √T⇒ λ1 = √T1 λ2 √T2 ⇒ λ2 = √ m1 - m2 λ1 m2 Correct Option: B
From figure, tension T1 = m2g
T2 = (m1 + m2)g
As we know
Velocity ∝ √T So,
λ ∝ √T⇒ λ1 = √T1 λ2 √T2 ⇒ λ2 = √ m1 - m2 λ1 m2
