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A uniform rope of length L and mass m1 hangs vertically from a rigid support. A block of mass m2 is attached to the free end of the rope. A transverse pulse of wavelength λ1 is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is λ2 the ratio λ2/λ1 is
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√ m1 m2 -
√ m1 + m2 m2 -
√ m2 m1 -
√ m1 + m2 m1
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Correct Option: B
From figure, tension T1 = m2g
T2 = (m1 + m2)g
As we know
Velocity ∝ √T So,
λ ∝ √T
| ⇒ | = | ||
| λ2 | √T2 |
| ⇒ | = √ | ||
| λ1 | m2 |
