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The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is
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- 100 cm
- 120 cm
- 140 cm
- 80 cm
Correct Option: B
Fundamental frequency of closed organ pipe
Vc = | ||
4lc |
Fundamental frequency of open organ pipe
V0 = | ||
2l0 |
Second overtone frequency of open organ pipe
= | ||
2l0 |
From question,
= | - | ||
4lc | 2l0 |
⇒ l0 = 6lc = 6 × 20 = 120 cm