Gravitation
- A satellite of mass m is orbiting around the earth in a circular orbit with a velocity v. What will be its total energy?
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Total energy = – K E = PE 2 = 1 mv2 2
Correct Option: D
Total energy = – K E = PE 2 = 1 mv2 2
- The mean radius of earth is R, its angular speed on its own axis is ω and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite ?
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T = 2πr = 2πr = 2πr3 / 2 = 2π v0 (gR2 / r)1 / 2 (gR2)1 / 2 ω Hence , r3 / 2 = √gR² or r3 = gR2 ω ω2
or r = (gR2 / ω2)1 / 3Correct Option: A
T = 2πr = 2πr = 2πr3 / 2 = 2π v0 (gR2 / r)1 / 2 (gR2)1 / 2 ω Hence , r3 / 2 = √gR² or r3 = gR2 ω ω2
or r = (gR2 / ω2)1 / 3
- The escape velocity from earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45° to the vertical, then the escape velocity is
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Escape velocity does not depend on the angle of projection.
Correct Option: B
Escape velocity does not depend on the angle of projection.
- A satellite in force free space sweeps stationary interplanetary dust at a rate dM/dt = αv where M is the mass and v is the velocity of the satellite and α is a constant. What is the deceleration of the satellite?
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F = dM v = αv2 ∵ dM = αv dt dt ∴ Retardation = -F = - αv2 M M
Correct Option: C
F = dM v = αv2 ∵ dM = αv dt dt ∴ Retardation = -F = - αv2 M M
- The escape velocity from the surface of the earth is ve.The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be
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Escape velocity on surface of earth
(ve) = √ 2GMe ∝ √ Me Re Re
or, vP= ve.Correct Option: A
Escape velocity on surface of earth
(ve) = √ 2GMe ∝ √ Me Re Re
or, vP= ve.