Electromagnetic Waves

Electromagnetic Waves

Easy Questions

Electricity and Magnetism

Current Electricity
Moving Charges and Magnetism
Magnetism and Matter
Electromagnetic Induction
Alternating Current
Electromagnetic Waves
  1. The velocity of electromagnetic radiation in a medium of permittivity ε0 and permeability µ0 is given by​​








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    The velocity of electromagnetic radiation in a medium of permittivity
    ∊0 and permeability µ0 is is equal to
    √μ0∊0

    Correct Option: C

    The velocity of electromagnetic radiation in a medium of permittivity
    ∊0 and permeability µ0 is is equal to
    √μ0∊0

  1. The electric field part of an electromagnetic wave in a medium is represented by Ex=0; ​
    = Ey = 2.5
    N
    		cos 2π × 106
    rad
    		 - 1π × 10-2
    rad
    		x;
    Cms

    ​Ez = 0. The wave is :​​








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    Comparing with the equation of wave.
    Ey = E0  cos (ωt – kx)
    ​ω = 2 πf = 2π × 106 
    ∴   f = 106  Hz
    2π/λ = K
    = π × 10-2 m-1, λ = 200 m

    Correct Option: B

    Comparing with the equation of wave.
    Ey = E0  cos (ωt – kx)
    ​ω = 2 πf = 2π × 106 
    ∴   f = 106  Hz
    2π/λ = K
    = π × 10-2 m-1, λ = 200 m

  1. Which of the following statement is false for the
    properties of electromagnetic waves?








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    ​Electromagnetic waves are the combination of mutually perpendicular electric and magnetic fields. So, option (c) is false.

    Correct Option: C

    ​Electromagnetic waves are the combination of mutually perpendicular electric and magnetic fields. So, option (c) is false.

  1. Out of the following options which one can be used to produce a propagating electromagnetic wave ?








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    ​To generate electromagnetic waves we need accelerating charge particle.

    Correct Option: D

    ​To generate electromagnetic waves we need accelerating charge particle.

  1. A radiation of energy ‘E’ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C = Velocity of light)








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    Momentum of light falling on reflecting surface

    p =
    E
    C

    As surface is perfectly reflecting so momentum reflect
    p1 = -
    E
    C


    So, momentum transferred
    = P - P1 =
    E
    		--
    E
    CC

    =
    2E
    C

    Correct Option: A

    Momentum of light falling on reflecting surface

    p =
    E
    C

    As surface is perfectly reflecting so momentum reflect
    p1 = -
    E
    C


    So, momentum transferred
    = P - P1 =
    E
    		--
    E
    CC

    =
    2E
    C