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Inversion of sucrose by immobilized invertase follows a substrate inhibited kinetics. The reaction rate (v) in mol m–3 hr–1 can be expressed
expressed as V = 800 [S]/ {400 + 50 [S] + [S]²}, where [S] is the sucrose concentration.
The immobilized invertase preparation is used in a CSTR with 100 mol m–3 sucrose concentration in the feed stream. If the reaction velocity passes through a maxima at [S] = 20 mol m–3, the feed flow rate for a reactor volume of 1m³ to get the maximum productivity from the reactor should be
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- 0.11 m³ hr–1
- 1.10 m³ hr–1
- 5.05 m³ hr–1
- None of these
Correct Option: D
| V = | ||
| 400 - 500[s] + [s]² |
S0 = 100 mol/m³ → V0 = 5.195 ml/m³ hr.
i.e. Vmax when S = 20 ml/m³,
∴ Vmax = 8.889 ml/m³.hr. V = (dp/dt)D = F/V
Now, Km = Vmax/2 = 4.444
Now,
V0 = Vmax = S/Km + S = 7.27 ml/m³. hr
