Direction: A solution was prepared by dissolving 100 mg of protein X in 100 ml of water.
Molecular weight of protein X is 15,000 Da; Avogadro’s number = 6.022 × 1023.
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The number of moleculespresent in this solution is
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- 40.15 × 1019
- 6.023 × 1019
- 4.015 × 1019
- 0.08 × 1019
- All to Marks
Correct Option: E
Number of moles present in the solution of protein = (100/15) = 6.667 moles
Number of molecules present in the solution = no. of moles × Avogadro’s number
= 6.667 × 6.022 × 1022
= 40.146 × 1022 molecules
