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Two plates are connected by fillet welds of size 10 mm and subjected to tension, as shown in the figure. The thickness of each plate is 12 mm. The yield stress and the ultimate tensile stress of steel are 250 MPa and 410 MPa, respectively. The welding is done in the workshop (γmw = 1.25). As per the Limit State Method of IS 800: 2007, the minimum length (rounded off to the nearest higher multiple of 5 mm) of each weld to transmit a force P equal to 270 kN is
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- 100 mm
- 105 mm
- 110 mm
- 115 mm
Correct Option: B
| P = |  |  | .tess.Less. | rmax |
tess = 0.7 × 10 = 7 mm
| ⇒ 210 × 103 = | × 7 × Less | 1.25 |
∴ Less = 192.82 ≈ 190
Provide extra widening
∴ resultant Less = 190 + 20 = 210 mm
∴ Each weld = 105 mm
