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Consider a computer system with 40-bit virtual addressing and page size of sixteen kilobytes. If the computer system has a one-level page table per process and each page table entry requires 48 bits, then the size of the perprocess page table is _________ megabytes.
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- 34 MB
- 1024 MB
- 24 MB
- 384 MB
Correct Option: D
Size of memory = 240, Page size = 16KB = 214, No. of pages = Size of Memory/page size = 240/214 = 226, Size of page table = 226 * 48/8 bytes = 26*6 MB = 384 MB
