Direction: A three span continuaous beam has a internal hinge at B section B is at the mind-span of AC. Section R is at the mid-span of CG. The 20 kN load is applied at section B whereas 10 kN loads are applied at sections D and F as shown in the figure span GH is subjected to uniformly distributed load of magnitude 5 kN/m. For the loading shown shear force immediate to the right of section E is 9.84 kN upwards and the sagging moment at section E is 10.3
AB = BC = 2 m
CD = DE = EF = FG = 1 m
GH = 4M
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The vertical reaction at support H is
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- 15 kN upward
- 9.84 kN upward
- 15 kN downward
- 9.84 kN downward
Correct Option: B
Consider section E H.
∑MG = 0
(RH × 4) + 10.31 – (9.48 × 2) + (10 × 1) – (5 × 4 × 2) = 0
RH = 9.84 kN
